0=-16t^2-40

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Solution for 0=-16t^2-40 equation: 



0=-16t^2-40

We move all terms to the left:

0-(-16t^2-40)=0

We add all the numbers together, and all the variables

-(-16t^2-40)=0

We get rid of parentheses

16t^2+40=0

a = 16; b = 0; c = +40;
Δ = b2-4ac
Δ = 02-4·16·40
Δ = -2560
Delta is less than zero, so there is no solution for the equation

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